String.prototype.charAt()

charAt()方法从一个字符串中返回指定的字符。

语法

str.charAt(index)

参数

描述

字符串中的字符从左向右索引，第一个字符的索引值为 0，最后一个字符（假设该字符位于字符串 stringName 中）的索引值为stringName.length - 1。如果指定的 index 值超出了该范围，则返回一个空字符串。

示例

例子：输出字符串中不同位置的字符

下例输出字符串"Brave new world"不同位置处的字符：

var anyString = "Brave new world";

console.log("The character at index 0   is '" + anyString.charAt(0)   + "'");
console.log("The character at index 1   is '" + anyString.charAt(1)   + "'");
console.log("The character at index 2   is '" + anyString.charAt(2)   + "'");
console.log("The character at index 3   is '" + anyString.charAt(3)   + "'");
console.log("The character at index 4   is '" + anyString.charAt(4)   + "'");
console.log("The character at index 999 is '" + anyString.charAt(999) + "'");

上面代码的输出为：

The character at index 0 is 'B'
The character at index 1 is 'r'
The character at index 2 is 'a'
The character at index 3 is 'v'
The character at index 4 is 'e'
The character at index 999 is ''

例子：获取所有字符

以下提供了一种确保通过字符串循环总是提供整个字符的方法，即使该字符串包含不在基本多文种平面（BMP）中的字符。

var str = 'A \uD87E\uDC04 Z'; // We could also use a non-BMP character directly
for (var i=0, chr; i  0xDFFF) {
    return str.charAt(i);
  }

  // High surrogate (could change last hex to 0xDB7F to treat high private
  // surrogates as single characters)
  if (0xD800  0xDFFF) {
    return [str.charAt(i), i]; // Normal character, keeping 'i' the same
  }

  // High surrogate (could change last hex to 0xDB7F to treat high private 
  // surrogates as single characters)
  if (0xD800 = end || idx 

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