scandir()

(PHP 5, PHP 7)

列出指定路径中的文件和目录

说明

返回一个array，包含有$directory中的文件和目录。

参数

要被浏览的目录

默认的排序顺序是按字母升序排列。如果使用了可选参数$sorting_order（设为 1），则排序顺序是按字母降序排列。

$context参数的说明见手册中的Streams API一章。

返回值

成功则返回包含有文件名的array，如果失败则返回FALSE。如果$directory不是个目录，则返回布尔值FALSE并生成一条E_WARNING级的错误。

更新日志

范例

一个简单的scandir()例子

以上例程的输出类似于：

Array
(
    [0] => .
    [1] => ..
    [2] => bar.php
    [3] => foo.txt
    [4] => somedir
)
Array
(
    [0] => somedir
    [1] => foo.txt
    [2] => bar.php
    [3] => ..
    [4] => .
)

Example #2scandir()在 PHP 4 中的实现

以上例程的输出类似于：

Array
(
    [0] => .
    [1] => ..
    [2] => bar.php
    [3] => foo.txt
    [4] => somedir
)
Array
(
    [0] => somedir
    [1] => foo.txt
    [2] => bar.php
    [3] => ..
    [4] => .
)

注释

如已启用fopen 包装器，在此函数中， URL 可作为文件名。关于如何指定文件名详见fopen()。各种wapper 的不同功能请参见支持的协议和封装协议，注意其用法及其可提供的预定义变量。

参见

• opendir() 打开目录句柄
• readdir() 从目录句柄中读取条目
• glob() 寻找与模式匹配的文件路径
• is_dir() 判断给定文件名是否是一个目录
• sort() 对数组排序

Easy way to get rid of the dots that scandir() picks up in Linux environments: 

Here is my 2 cents. I wanted to create an array of my directory structure recursively. I wanted to easely access data in a certain directory using foreach. I came up with the following:

Output
Array
(
  [subdir1] => Array
  (
   [0] => file1.txt
   [subsubdir] => Array
   (
     [0] => file2.txt
     [1] => file3.txt
   )
  )
  [subdir2] => Array
  (
  [0] => file4.txt
  }
)

Someone wrote that array_slice could be used to quickly remove directory entries "." and "..". However, "-" is a valid entry that would come before those, so array_slice would remove the wrong entries.

Fastest way to get a list of files without dots.

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