DirectoryIterator::__construct() - 迭代器
DirectoryIterator::__construct()
(PHP 5,PHP 7)
Constructs a new directory iterator from a path
说明
publicDirectoryIterator::__construct(string $path)Constructs a new directory iterator from a path.
参数
$pathThe path of the directory to traverse.
错误/异常
Throws anUnexpectedValueExceptionif the$pathcannot be opened.
Throws aRuntimeExceptionif the$pathis an empty string.
更新日志
版本 | 说明 |
---|---|
5.3.0 | ThrowsUnexpectedValueExceptionif the$pathcannot be opened. |
5.1.3 | ThrowsRuntimeExceptionif the$pathis an empty string. |
5.1.0 | ThrowsRuntimeExceptionon error.Previously,threwException. |
范例
Example#1 ADirectoryIterator::__construct()example
This example will list the contents of the directory containing the script.
参见
- SplFileInfo
- Iterator
Here's all-in-one DirectoryIterator: Some examples: Presumably, this approach is memory intensive as well.
I needed to match in directory tree file name(s) by regular expression. Code is based on Marcus Börger class DirectoryTreeIterator http://cvs.php.net/viewvc.cgi/php-src/ext/spl/examples/ and on examples given in his lecture Introduction to object oriented PHP at PHP Quebec conference 2007 http://talks.somabo.de/
Beware that DirectoryIterator returns a reference to itself with each iteration instead of a unique new SplFileInfo object as one may first assume. This is important to know if you want to push the results of an iteration into an array for later processing. If you do that, then all entries in the array will be the same DirectoryIterator object with the same internal state (most likely invalid - see the valid() method), which is probably not what you want. So if you do want to store the iteration results in an array, then you must convert them to either plain strings or new SplFileInfo objects first. $todo = []; foreach (new DirectoryIterator('/some/dir') as $entry) { if (!$entry->isFile()) { continue; } #$todo []= $entry; # Don't do this! $todo []= new SplFileInfo($entry->getFilename()); # Do this! #$todo []= $entry->getFilename(); # or do this if you're only interested in the file name. }
I need to traverse recursively through a directory tree and get all sub-directory paths and has written a snippet to do that.
udvig dot ericson at gmail dot com 29-Jul-2006 07:48 In response to the comment below from udvig. The Example ist wrong, here is the right one:
We can now replace the old fashioned way of listing the content from a directory! the old way: the new way:
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