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ArrayObject::getArrayCopy() - 各种类及接口

梵高12个月前 (11-21)阅读数 14#技术干货
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ArrayObject::getArrayCopy()

(PHP 5, PHP 7)

Creates a copy of the ArrayObject

说明

publicArrayObject::getArrayCopy(void): array

ArrayObject::getArrayCopy() - 各种类及接口

Exports the ArrayObject to an array.

参数

此函数没有参数。

返回值

Returns a copy of the array. When the ArrayObject refers to an object, an array of the public properties of that object will be returned.

范例

ArrayObject::getArrayCopy() example

以上例程会输出:

Array
(
    [lemons] => 1
    [oranges] => 4
    [bananas] => 5
    [apples] => 10
    [pears] => 4
)
Is there a difference between casting to an array and using this function?
For instance, if we have:
$arrayObject = new ArrayObject([1, 2, 3]);
Is there a difference between these:
$array = (array) $arrayObject;
vs
$array = $arrayObject->getArrayCopy();
If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:

That’s the way I solved it:

Hope this was useful!
"When the ArrayObject refers to an object an array of the public properties of that object will be returned."
This description does not seem to be right:

So it does not only include the public properties.
When I used print_r ($fruitsArrayObject) instead of print_r ($copy), i.e. ignoring the getArrayCopy() step, I still got the same output. Why?
will NOT be magically called if you cast to array. Although I've expected it.

Here, $data != $nothing.

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