unixtojd()

(PHP 4, PHP 5, PHP 7)

转变Unix时间戳为Julian Day计数

说明

根据指定的Unix时间戳$timestamp，返回Julian天数。如果没有指定时间戳则返回当前日期的天数。

参数

一个用于转变的时间戳。

返回值

一个julian天数。

参见

• jdtounix()转变Julian Day计数为一个Unix时间戳

If you need an easy way to convert an unix timestamp to a decimal julian day you can use:
$julianDay = $unixTimeStamp / 86400 + 2440587.5;
86400 is the number of seconds in a day;
2440587.5 is the julian day at 1/1/1970 0:00 UTC.

Its clearly stated that this function returns the Julian Day, not Julian Day + time.
If you want the time with it you will have to do something like:
$t=time();
$jd=unixtojd($t)+($t%60*60*24)/60*60*24;

according to http://www.decimaltime.hynes.net/dates.html#jd and reading "X. Calendar Functions" on this side, it seems that php "jd" is precisely mean as "Chronological Julian Day" (should it be named cjd, and primarily strictly mentioned - isn't it?), used for covnersion between calendar systems. Than it's ok (but Incomplete manual is strongly confusing here IMHO).
Even that, cJD is adjusted to a local time, so... I am rather babeled now, so nothing else :-).

This is unusable. Julian Day start at noon, not midnight. It's better to use Fabio solution (however there is a lurk problem with leap second).

reference
unix time, and UTC, TAI, ntp, ... problems: http://en.wikipedia.org/wiki/Unix_time
Julian Date Converter: http://aa.usno.navy.mil/data/docs/JulianDate.html
history overview: http://parris.josh.com.au/humour/work/17Nov1858.shtml

Also note that epoch is in UTC time (epoch is a specific point in time - epoch is not different for every time zone), so be aware of timezone complexities.

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