《天谕手游》孤高的浮云乐谱代码分享

天谕手游当中，玩家可以把自己喜欢的音乐写进乐谱，很多玩家想知道孤高的浮云乐谱代码是怎样的。接下来就让我给大家带来《天谕手游》孤高的浮云乐谱代码分享，感兴趣的玩家一起来看看吧。

我推荐： 《天谕手游》乐谱代码汇总

t127

A轨

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B轨

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乐谱代码使用方法

1.首先找到一首歌曲的代码，然后复制下来；

2.然后打开天谕手游-游戏中界面-演奏的功能键(在相机右边，只有乐师职业才会有)；

3.点击这个功能键展开，就会有谱曲的功能，点击进入，选择新建曲谱，然后把保存代码复制进去；

4.曲谱分为音轨A、音轨B、音轨C，玩家可以都复制粘贴，然后点击右侧的保存键即可导入成功，之后在自动演奏中就可以播放了。

（1）由图可知，水的分解化学键断裂先生成H原子与O原子，氢原子结合生成氢气，氧原子结合生成氧气，由水的分子式可知氢原子物质的量是氧原子2倍，故A为氢原子、B为氧原子；

氧原子和氢原子生成水时不需要断裂化学键，所以其活化能=0，

故答案为：氢原子、氧原子；=；

（2）含有6.02×1022个氢原子的氢气的物质的量=

标况下氢气的体积=0.05mol×22.4L/mol=1.12L=1120mL；

负极上失电子发生氧化反应，电极反应式为LaNi5H6+6OH--6e-═LaN5+6H2O，

故答案为：1120；LaNi5H6+6OH--6e-═LaN5+6H2O；

（3）①根据图象知，二氧化碳的反应速率=

故答案为：0.075mol/（L?min）；

②根据反应方程式知，平衡时c（CH3OH）=c（H2O）=0.75mol/L，c（CO2）=0.25mol/L，根据甲醇和氢气的关系式知，平衡时氢气浓度=3mol/L-3×0.75mol/L=0.75mol/L，

平衡常数K=

故答案为：

③该反应是一个反应前后气体体积减小的、放热的可逆反应，降低温度、增大压强、增大氢气的量或减少生成物的量都增大二氧化碳的转化率，

故选：CE．

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