设∠AOB=X那么∠COB=180-XOD是角AOB的角平分线。OE在角BOC内，角BOE=1/2角EOC所以∠DOB=X/2∠EOB=(180-X)/3∠EOC=2(180-X)/3∠DOE=∠DOB+∠EOB=X/2+(180-X)/3...
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